Factorising Quadratics

Grade 5

What you are looking for

To factorise x² + bx + c, you need two numbers that add to b and multiply to c. Call them p and q. Then the factorised form is (x + p)(x + q).

This works because expanding (x + p)(x + q) gives x² + (p + q)x + pq. So the sum and product of your two numbers must match b and c.

Worked example

EXAMPLE
Factorise x² + 7x + 12.
Need two numbers that add to 7 and multiply to 12. Try 3 and 4: 3 + 4 = 7 ✓, 3 × 4 = 12 ✓. Answer: (x + 3)(x + 4). Check: expand to get x² + 4x + 3x + 12 = x² + 7x + 12. ✓

When the coefficient of x² is not 1

For ax² + bx + c where a ≠ 1, you need to find two numbers that multiply to a × c and add to b. Then split the middle term and factorise by grouping. This is called the ac method.

EXAMPLE
Factorise 2x² + 5x + 3.
a × c = 2 × 3 = 6. Need two numbers that multiply to 6 and add to 5: that is 2 and 3. Split: 2x² + 2x + 3x + 3. Group: 2x(x + 1) + 3(x + 1) = (2x + 3)(x + 1).

Always check

Expand your answer back out. If you get the original expression, you are done. This takes 20 seconds and catches every sign error.
Nova
Try this one

(a) Factorise \( x^2 - 3x - 10 \). [2]

(b) Hence solve \( x^2 - 3x - 10 = 0 \). [1]

Nova's hint:

Part (a) uses factorising a quadratic — find two numbers that multiply to the constant term and add to the coefficient of \( x \).

Ask yourself: 'Once I have the factorised form \( (x + a)(x + b) = 0 \), what must be true about at least one of the brackets for the product to equal zero?'

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